(3x^2)(4x^-3)+4=15

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Solution for (3x^2)(4x^-3)+4=15 equation: 



(3x^2)(4x^-3)+4=15

We move all terms to the left:

(3x^2)(4x^-3)+4-(15)=0

We add all the numbers together, and all the variables

3x^2(4x^-3)-11=0

We move all terms containing x to the left, all other terms to the right

3x^2(4x^-3)=11

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